4[3x-4(5x+y)]=0

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Solution for 4[3x-4(5x+y)]=0 equation: 


Simplifying
4[3x + -4(5x + y)] = 0
4[3x + (5x * -4 + y * -4)] = 0
4[3x + (-20x + -4y)] = 0

Combine like terms: 3x + -20x = -17x
4[-17x + -4y] = 0
[-17x * 4 + -4y * 4] = 0
[-68x + -16y] = 0

Solving
-68x + -16y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '16y' to each side of the equation.
-68x + -16y + 16y = 0 + 16y

Combine like terms: -16y + 16y = 0
-68x + 0 = 0 + 16y
-68x = 0 + 16y
Remove the zero:
-68x = 16y

Divide each side by '-68'.
x = -0.2352941176y

Simplifying
x = -0.2352941176y

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